JS Quiz: 9 Promise Questions
Never drop a promise again!
Do you know JavaScript Promises?
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👇 Complete 9 Questions Below👇
What will the output be for the following code?
var p = new Promise((resolve, reject) => {
reject(Error('The Fails!'))
})
p.catch(error => console.log(error.message))
p.catch(error => console.log(error.message))
We create a Promise using the constructor method, triggering an error immediately with the reject callback.
Then the .catch handlers work like the DOM’s .addEventListener(event, callback) or Event Emitter’s .on(event, callback) where multiple handler callbacks can be added. Each will be called with the same arguments.
What will the output be for the following code?
var p = new Promise((resolve, reject) => {
return Promise.reject(Error('The Fails!'))
})
p.catch(error => console.log(error.message))
p.catch(error => console.log(error.message))
When using the Promise constructor you must invoke either resolve() or reject() callbacks. The Promise constructor doesn’t use your return value, so the additional Promise created with Promise.reject() will effectively never be heard from again.
What will the output be for the following code?
var p = new Promise((resolve, reject) => {
reject(Error('The Fails!'))
})
.catch(error => console.log(error))
.then(error => console.log(error))
When chaining .then’s and .catch’s it is helpful to think of them as a series of steps. Each .then receives the value returned by the previous .then (as its argument.) However, if your “step” encountered an error, any subsequent .then “steps” will be skipped until a .catch is encountered. If you want to override an error, all you need to do is return a non-error value. It can be accessed via any subsequent .then.
What will the output be for the following code?
var p = new Promise((resolve, reject) => {
reject(Error('The Fails!'))
})
.catch(error => console.log(error.message))
.catch(error => console.log(error.message))
When chaining .catch’s, each one only handles errors thrown in previous .then or .catch “steps”. In this example the first .catch returns the console.log which could only be accessed via adding a .then() after both the .catch’s.
What will the output be for the following code?
new Promise((resolve, reject) => {
resolve('Success!')
})
.then(() => {
throw Error('Oh noes!')
})
.catch(error => {
return "actually, that worked"
})
.catch(error => console.log(error.message))
Hint: .catch’s can be used to ignore (or override) errors simply by returning a regular value.
This trick works only when there is a subsequent .then to receive the value.
What will the output be for the following code?
Promise.resolve('Success!')
.then(data => {
return data.toUpperCase()
})
.then(data => {
console.log(data)
})
Hint: .then’s pass data sequentially, from return value to the next .then(value => /* handle value */).
A return is key in order to pass a value to the next .then.
What will the output be for the following code?
Promise.resolve('Success!')
.then(data => {
return data.toUpperCase()
})
.then(data => {
console.log(data)
return data
})
.then(console.log)
There are 2 console.log calls which will be called.
What will the output be for the following code?
Promise.resolve('Success!')
.then(data => {
data.toUpperCase()
})
.then(data => {
console.log(data)
})
Hint: .then’s pass data sequentially, from return value to the next .then(value => /* handle value */).
A return is key in order to pass a value to the next .then.
What will the output be for the following code?
Promise.resolve('Success!')
.then(() => {
throw Error('Oh noes!')
})
.catch(error => {
return 'actually, that worked'
})
.then(data => {
throw Error('The fails!')
})
.catch(error => console.log(error.message))
